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Four Forces Series · Paper VI

质子为什么不衰变

Why the Proton Doesn't Decay

Spin(10)是分类群,不是规范群——大统一预测的根本性盲区

Spin(10) is a classifier, not a gauge group — the fundamental blind spot of GUT predictions

DOI 10.5281/zenodo.19426067
DOI 10.5281/zenodo.19426067
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大统一的预测与实验的沉默

大统一理论(GUT)预测质子会衰变。最简单的SU(5) GUT预测质子寿命约10³¹年,通过p → π⁰ + e⁺通道。Super-K实验观测了超过2万吨水中的质子长达数十年,没有发现这个衰变道的任何信号。

标准响应是:SU(5) GUT已死,需要更复杂的GUT,比如SO(10)。SO(10) GUT中,一代所有费米子(含右手中微子)恰好填满一个16维旋量表示16。这个数学上的漂亮让很多物理学家相信SO(10)(或其覆叠群Spin(10))是真正的统一群。

SAE的问题:Spin(10)的16维表示是真的吗?当然。但Spin(10)是规范群吗?

分类群与规范群的区别

规范群是局域对称性,产生规范玻色子,交换玻色子实现相互作用。分类群是对态的整体分类工具,不产生动力学。

四力篇VI从DD Splitting定理出发构造Spin(10)的16维骨架:三对4DD pair轴的大小定向各提供一个Z₂因子,L/R手征提供第四个Z₂因子,四个Z₂的16态经Weyl条件恰好给出Spin(10)的旋量表示16 = (4,2,1) ⊕ (4̄,1,2)。

这16态与一代费米子完全匹配——不是巧合,而是DD结构的直接输出。

但这个Spin(10)是分类群:它把一代费米子分类。它不是动力学规范群,因为4DD block的大小定向不是可以随时空连续变化的局域对称参数。

五条硬反预测

如果Spin(10)只是分类群而非规范群,则GUT依赖Spin(10)规范对称性的一系列预测全部错误:

1. 质子不通过规范介导通道衰变(实验一致)

2. 没有精确的单一能标规范耦合统一(SAE anti-GUT)

3. 规范玻色子数 = 12(来自N_blocks),不是Spin(10)的45

4. 轻子是Λ³U的体积元,不是第四种颜色(解释了轻子-夸克对称性的来源,又维持了轻子-夸克的不同性质)

5. L-R对称性在结构上可能破缺(来自L-R canonical配对的桥接假设)

这些反预测中,最重要的是质子不衰变(通道1)。Super-K继续运行,下一代实验Hyper-K正在建设,更强的约束即将到来。SAE的预测明确:质子寿命通过规范介导通道是无穷大(不是10³⁵年,而是∞)。实验每次没有看到信号,都是对SAE的一次支持。

Grand Unified Predictions and Experimental Silence

Grand Unified Theories (GUTs) predict proton decay. The simplest SU(5) GUT predicts a proton lifetime of roughly 10³¹ years, through the p → π⁰ + e⁺ channel. Super-K has monitored over 20,000 tons of water for decades, finding no signal for this decay mode.

The standard response: SU(5) GUT is dead; we need a more complex GUT, such as SO(10). In SO(10) GUT, one entire generation of fermions (including the right-handed neutrino) fits perfectly into a single 16-dimensional spinor representation 16. This mathematical elegance has convinced many physicists that SO(10) (or its covering group Spin(10)) is the true unification group.

SAE's question: Is Spin(10)'s 16-dimensional representation real? Absolutely. But is Spin(10) a gauge group?

The Difference Between a Classifier and a Gauge Group

A gauge group is a local symmetry that generates gauge bosons; exchanging bosons implements the interaction. A classifier is a global tool for organizing states — it produces no dynamics.

Four Forces Paper VI constructs the 16-dimensional Spin(10) skeleton from DD Splitting: three pairs of 4DD block axes each contribute one Z₂ factor from their orientation; L/R chirality contributes a fourth Z₂; the 16 states from four Z₂ factors, under the Weyl condition, give exactly Spin(10)'s spinor representation 16 = (4,2,1) ⊕ (4̄,1,2).

These 16 states perfectly match one fermion generation — not by coincidence, but as direct output of DD structure.

But this Spin(10) is a classifier: it classifies one fermion generation. It is not a dynamical gauge group, because the orientation of 4DD blocks is not a local symmetry parameter that varies continuously with spacetime.

Five Hard Anti-Predictions

If Spin(10) is only a classifier and not a gauge group, then a whole series of GUT predictions relying on Spin(10) gauge symmetry are wrong:

1. The proton does not decay through gauge-mediated channels (consistent with experiment)

2. No exact single-scale gauge coupling unification (SAE anti-GUT)

3. The number of gauge bosons = 12 (from N_blocks), not Spin(10)'s 45

4. Leptons are volume elements Λ³U, not a fourth color (explaining lepton-quark symmetry's origin while preserving lepton-quark distinction)

5. L-R symmetry may be structurally broken (from the L-R canonical pairing bridge hypothesis)

Of these anti-predictions, the most important is proton non-decay (channel 1). Super-K continues to run; the next-generation experiment Hyper-K is under construction, bringing stronger constraints. SAE's prediction is explicit: proton lifetime through gauge-mediated channels is infinite — not 10³⁵ years, but ∞. Every null experimental result is a confirmation of SAE.